Atomistry » Lead » Energy
Atomistry »
  Lead »
    Energy »

Lead Ionization Energy

The Lead Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Lead.
Pb -> Pb+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Lead is:
PbN+ -> Pb(N+1)+ + e-

Ionization Energy

Pb -> Pb1+ = 715.5 kJ/mol = 171.17 Kcal/mol
Pb1+ -> Pb2+ = 1450.4 kJ/mol = 346.99 Kcal/mol
Pb2+ -> Pb3+ = 3081.5 kJ/mol = 737.20 Kcal/mol
Pb3+ -> Pb4+ = 4083 kJ/mol = 976.79 Kcal/mol
Pb4+ -> Pb5+ = 6640 kJ/mol = 1588.52 Kcal/mol
Pb5+ -> Pb6+ = 8100 kJ/mol = 1937.80 Kcal/mol
Pb6+ -> Pb7+ = 9900 kJ/mol = 2368.42 Kcal/mol
Pb7+ -> Pb8+ = 11800 kJ/mol = 2822.97 Kcal/mol
Pb8+ -> Pb9+ = 13700 kJ/mol = 3277.51 Kcal/mol
Pb9+ -> Pb10+ = 16700 kJ/mol = 3995.22 Kcal/mol

Last articles

Fe in 2YXO
Fe in 2YRS
Fe in 2YXC
Fe in 2YNM
Fe in 2YVJ
Fe in 2YP1
Fe in 2YU2
Fe in 2YU1
Fe in 2YQB
Fe in 2YOO
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy