Lead Ionization Energy

The Lead Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Lead.
Pb -> Pb⁺ + e^-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Lead is:
Pb^N+ -> Pb^(N+1)+ + e^-

Pb -> Pb¹⁺ = 715.5 kJ/mol = 171.17 Kcal/mol
Pb¹⁺ -> Pb²⁺ = 1450.4 kJ/mol = 346.99 Kcal/mol
Pb²⁺ -> Pb³⁺ = 3081.5 kJ/mol = 737.20 Kcal/mol
Pb³⁺ -> Pb⁴⁺ = 4083 kJ/mol = 976.79 Kcal/mol
Pb⁴⁺ -> Pb⁵⁺ = 6640 kJ/mol = 1588.52 Kcal/mol
Pb⁵⁺ -> Pb⁶⁺ = 8100 kJ/mol = 1937.80 Kcal/mol
Pb⁶⁺ -> Pb⁷⁺ = 9900 kJ/mol = 2368.42 Kcal/mol
Pb⁷⁺ -> Pb⁸⁺ = 11800 kJ/mol = 2822.97 Kcal/mol
Pb⁸⁺ -> Pb⁹⁺ = 13700 kJ/mol = 3277.51 Kcal/mol
Pb⁹⁺ -> Pb¹⁰⁺ = 16700 kJ/mol = 3995.22 Kcal/mol