Atomistry » Lead » Energy
Atomistry »
  Lead »
    Energy »

Lead Ionization Energy

The Lead Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Lead.
Pb -> Pb+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Lead is:
PbN+ -> Pb(N+1)+ + e-

Ionization Energy

Pb -> Pb1+ = 715.5 kJ/mol = 171.17 Kcal/mol
Pb1+ -> Pb2+ = 1450.4 kJ/mol = 346.99 Kcal/mol
Pb2+ -> Pb3+ = 3081.5 kJ/mol = 737.20 Kcal/mol
Pb3+ -> Pb4+ = 4083 kJ/mol = 976.79 Kcal/mol
Pb4+ -> Pb5+ = 6640 kJ/mol = 1588.52 Kcal/mol
Pb5+ -> Pb6+ = 8100 kJ/mol = 1937.80 Kcal/mol
Pb6+ -> Pb7+ = 9900 kJ/mol = 2368.42 Kcal/mol
Pb7+ -> Pb8+ = 11800 kJ/mol = 2822.97 Kcal/mol
Pb8+ -> Pb9+ = 13700 kJ/mol = 3277.51 Kcal/mol
Pb9+ -> Pb10+ = 16700 kJ/mol = 3995.22 Kcal/mol

Last articles

Zn in 7VD8
Zn in 7V1R
Zn in 7V1Q
Zn in 7VPF
Zn in 7T85
Zn in 7T5F
Zn in 7NF9
Zn in 7M4M
Zn in 7M4O
Zn in 7M4N
© Copyright 2008-2020 by atomistry.com
Home   |    Site Map   |    Copyright   |    Contact us   |    Privacy