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Lead Ionization Energy

The Lead Ionization Energy is the energy required to remove from atom one mole of electrons with subsequent production of positively charged ion of Lead.
Pb -> Pb+ + e-
This process can be repeated many times, but the energy cost is increased dramatically. The general equation for the Lead is:
PbN+ -> Pb(N+1)+ + e-

Ionization Energy

Pb -> Pb1+ = 715.5 kJ/mol = 171.17 Kcal/mol
Pb1+ -> Pb2+ = 1450.4 kJ/mol = 346.99 Kcal/mol
Pb2+ -> Pb3+ = 3081.5 kJ/mol = 737.20 Kcal/mol
Pb3+ -> Pb4+ = 4083 kJ/mol = 976.79 Kcal/mol
Pb4+ -> Pb5+ = 6640 kJ/mol = 1588.52 Kcal/mol
Pb5+ -> Pb6+ = 8100 kJ/mol = 1937.80 Kcal/mol
Pb6+ -> Pb7+ = 9900 kJ/mol = 2368.42 Kcal/mol
Pb7+ -> Pb8+ = 11800 kJ/mol = 2822.97 Kcal/mol
Pb8+ -> Pb9+ = 13700 kJ/mol = 3277.51 Kcal/mol
Pb9+ -> Pb10+ = 16700 kJ/mol = 3995.22 Kcal/mol

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